∫ 2/π(sin-¹x + cos-¹x)dx

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Q-: ∫ 2/π(sin-¹x + cos-¹x)dx =
(A) π/2 + x + k
(B) πx/2 + k
(C) x + K
(D) 0
Answer -: x + K 

Solution 👇👇👇

 

 

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